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Answered on 18 Apr Learn Sphere

Nazia Khanum

Introduction In this explanation, I'll guide you through the process of finding the volume of a sphere when its radius is given as 3r. Formula for the Volume of a Sphere The formula for calculating the volume of a sphere is: V=43πr3V=34πr3 Where: VV = Volume of the sphere ππ = Pi (approximately... read more

Introduction

In this explanation, I'll guide you through the process of finding the volume of a sphere when its radius is given as 3r.

Formula for the Volume of a Sphere

The formula for calculating the volume of a sphere is:

V=43πr3V=34πr3

Where:

  • VV = Volume of the sphere
  • ππ = Pi (approximately 3.14159)
  • rr = Radius of the sphere

Given Information

Given that the radius of the sphere is 3r, we'll substitute r=3rr=3r into the formula.

Calculation

Substituting r=3rr=3r into the formula, we get:

V=43π(3r)3V=34π(3r)3

V=43π27r3V=34π27r3

V=36πr3V=36πr3

Conclusion

The volume of the sphere when the radius is 3r is 36πr336πr3.


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Answered on 18 Apr Learn Sphere

Nazia Khanum

Finding the Volume of a Cube Understanding the Problem To find the volume of a cube, we first need to understand the given information: Total surface area of the cube is 216 cm². Solution Steps Determine the Side Length of the Cube Since a cube has six equal square faces, the total surface... read more

Finding the Volume of a Cube

Understanding the Problem

To find the volume of a cube, we first need to understand the given information:

  • Total surface area of the cube is 216 cm².

Solution Steps

  1. Determine the Side Length of the Cube

    • Since a cube has six equal square faces, the total surface area can be expressed as 6s26s2, where ss is the side length of the cube.
    • So, 6s2=216 cm26s2=216cm2.
    • Solving for ss, we get s=2166s=6216

 

    • .
  • Calculate the Volume of the Cube

    • Once we have the side length, we can calculate the volume of the cube using the formula V=s3V=s3.
    • Substituting the value of ss, we get V=(2166)3V=(6216

 

    • )3.
    • Simplify to find the volume.

Detailed Calculation

  1. Determine the Side Length of the Cube

    • Given: Total surface area (AA) = 216 cm².
    • Formula for total surface area: A=6s2A=6s2.
    • Substitute the given value: 216=6s2216=6s2.
    • Solve for ss: s=2166s=6216

 

  • .
  • Calculate: s=36s=36

 

    • .
    • Thus, s=6 cms=6cm.
  1. Calculate the Volume of the Cube

    • Formula for volume: V=s3V=s3.
    • Substitute the value of ss: V=63V=63.
    • Calculate: V=216 cm3V=216cm3.

Final Answer

  • The volume of the cube is 216 cm3216cm3.
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Answered on 18 Apr Learn Sphere

Nazia Khanum

Finding the Base Area of a Right Circular Cylinder Understanding the Problem To find the base area of a right circular cylinder, we need to utilize the given information about its circumference. Given Information: Circumference of the base: 110 cm Solution Steps: Determine the Radius: The circumference... read more

Finding the Base Area of a Right Circular Cylinder

Understanding the Problem To find the base area of a right circular cylinder, we need to utilize the given information about its circumference.

Given Information:

  • Circumference of the base: 110 cm

Solution Steps:

  1. Determine the Radius:
    • The circumference of a circle CC is given by the formula: C=2πrC=2πr.
    • Given C=110C=110 cm, we can rearrange the formula to solve for the radius rr: 110=2πr110=2πr Solving for rr: r=1102πr=2π110
  2. Calculate the Base Area:
    • The formula for the area AA of a circle is: A=πr2A=πr2.
    • Plug in the value of rr obtained from step 1 into the formula: A=π(1102π)2A=π(2π110)2 Simplify: A=π(11024π2)A=π(4π21102) A=11024πA=4π1102
  3. Final Calculation:
    • Calculate the value of AA: A=121004πA=4π12100 A≈3035.5πA≈π3035.5 A≈964.88A≈964.88 sq. cm (rounded to two decimal places)

Conclusion:

  • The base area of the right circular cylinder is approximately 964.88964.88 square centimeters.
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Answered on 18 Apr Learn Sphere

Nazia Khanum

To find the cost of the cloth required to make a conical tent, we'll need to: Calculate the slant height of the conical tent. Find the total surface area of the tent. Determine the length of cloth required. Calculate the cost of the cloth. Solution: Step 1: Calculate Slant Height (l) Given: Radius... read more

To find the cost of the cloth required to make a conical tent, we'll need to:

  1. Calculate the slant height of the conical tent.
  2. Find the total surface area of the tent.
  3. Determine the length of cloth required.
  4. Calculate the cost of the cloth.

Solution:

Step 1: Calculate Slant Height (l)

Given:

  • Radius (r) = 7 m
  • Height (h) = 24 m

Using Pythagoras theorem, we can find the slant height (l) of the cone: l=r2+h2l=r2+h2

l=72+242l=72+242

l=49+576l=49+576 l=625l=625

l=25 ml=25m

Step 2: Find Total Surface Area of the Tent

Total surface area (A) of a cone is given by: A=πr(r+l)A=πr(r+l)

A=π×7×(7+25)A=π×7×(7+25) A=π×7×32A=π×7×32 A≈704 m2A≈704m2

Step 3: Determine Length of Cloth Required

Given:

  • Width of cloth (w) = 5 m

The length of cloth required will be equal to the circumference of the base of the cone, which is: C=2πrC=2πr

C=2π×7C=2π×7 C≈44 mC≈44m

Step 4: Calculate Cost of Cloth

Given:

  • Rate of cloth (R) = Rs. 50 per meter

The cost of cloth required will be: Cost=Length of cloth required×Rate of clothCost=Length of cloth required×Rate of cloth

Cost=44×50Cost=44×50 Cost=Rs.2200Cost=Rs.2200

Conclusion:

The cost of the 5 m wide cloth required at the rate of Rs. 50 per metre is Rs. 2200.

 
 
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Answered on 18 Apr Learn Real Numbers

Nazia Khanum

Visualizing 3.765 on the Number Line Introduction Visualizing numbers on a number line can be a helpful technique to understand their placement and relationship to other numbers. Let's explore how we can visualize the number 3.765 using successive magnification. Steps to Visualize 3.765 Identify... read more

Visualizing 3.765 on the Number Line

Introduction

Visualizing numbers on a number line can be a helpful technique to understand their placement and relationship to other numbers. Let's explore how we can visualize the number 3.765 using successive magnification.

Steps to Visualize 3.765

  1. Identify the Initial Position:

    • Start with the number 3.765 on the number line.
  2. First Magnification:

    • Zoom in on the integer part, 3, of the number.
    • Place 3 on the number line and divide the interval between 3 and 4 into ten equal parts.
    • Locate the position of 0.765 within this interval. Since 0.765 lies between 0 and 1, it would be helpful to break down the interval further.
  3. Second Magnification:

    • Zoom in on the interval between 3 and 4.
    • Divide this interval into ten equal parts again.
    • Now, locate the position of 0.765 within this smaller interval.
    • Continue this process of successive magnification until you reach a level of detail that allows you to pinpoint the position of 0.765 accurately.
  4. Final Visualization:

    • After several magnifications, you'll notice that 0.765 falls between two consecutive integers on the number line.
    • Approximate the position of 0.765 relative to the nearest integers, 3 and 4, based on the magnification level.

Conclusion

Visualizing numbers on the number line using successive magnification helps in understanding their precise location and relationship to other numbers. By breaking down the intervals into smaller parts, we can accurately locate decimal numbers like 3.765 on the number line.

 
 
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Answered on 18 Apr Learn Real Numbers

Nazia Khanum

Adding Radical Expressions Introduction: In mathematics, adding radical expressions involves combining like terms to simplify the expression. Radical expressions contain radicals, which are expressions that include square roots, cube roots, etc. Problem Statement: Add 22+5322 +53 and 2−332−33 . Solution:... read more

Adding Radical Expressions

Introduction: In mathematics, adding radical expressions involves combining like terms to simplify the expression. Radical expressions contain radicals, which are expressions that include square roots, cube roots, etc.

Problem Statement: Add 22+5322

+53 and 2−332−33

.

Solution: To add radical expressions, follow these steps:

  1. Identify Like Terms:

    • 2222

and 22

  • are like terms.
  • 5353

and −33−33

    • are like terms.
  • Combine Like Terms:

    • Add the coefficients of like terms:
      • For 22
  • : 2+1=32+1=3
  • For 33
      • : 5−3=25−3=2
  • Write the Result:

    • The sum of 22+5322

+53 and 2−332−33 is:

 

  • 32+2332

+23

      • .

Conclusion: The addition of 22+5322

+53 and 2−332−33 simplifies to 32+2332+23

.

 
 
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Answered on 18 Apr Learn Linear equations in 2 variables

Nazia Khanum

Introduction: In this problem, we are tasked with verifying whether the values x=2x=2 and y=1y=1 satisfy the linear equation 2x+3y=72x+3y=7. Verification: We'll substitute the given values of xx and yy into the equation and check if it holds true. Given Equation: 2x+3y=72x+3y=7 Substituting Given... read more

Introduction: In this problem, we are tasked with verifying whether the values x=2x=2 and y=1y=1 satisfy the linear equation 2x+3y=72x+3y=7.

Verification: We'll substitute the given values of xx and yy into the equation and check if it holds true.

Given Equation: 2x+3y=72x+3y=7

Substituting Given Values:

  • Substitute x=2x=2 and y=1y=1 into the equation. 2(2)+3(1)=72(2)+3(1)=7

Solving the Equation: 4+3=74+3=7 7=77=7

Conclusion:

  • Since the equation simplifies to 7=77=7, it confirms that x=2x=2 and y=1y=1 satisfy the linear equation 2x+3y=72x+3y=7.

Therefore, the given values x=2x=2 and y=1y=1 indeed satisfy the linear equation 2x+3y=72x+3y=7.

 
 
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Answered on 18 Apr Learn Polynomials

Nazia Khanum

Problem Analysis: Given equations: 3x+2y=123x+2y=12 xy=6xy=6 We need to find the value of 9x2+4y29x2+4y2. Solution: Step 1: Find the values of xx and yy To solve the system of equations, we can use substitution or elimination method. From equation (2), xy=6xy=6, we can express yy in terms of xx:... read more

Problem Analysis: Given equations:

  1. 3x+2y=123x+2y=12
  2. xy=6xy=6

We need to find the value of 9x2+4y29x2+4y2.

Solution:

Step 1: Find the values of xx and yy

To solve the system of equations, we can use substitution or elimination method.

From equation (2), xy=6xy=6, we can express yy in terms of xx: y=6xy=x6

Substitute this expression for yy into equation (1): 3x+2(6x)=123x+2(x6)=12

Now solve for xx:

3x+12x=123x+x12=12 3x2+12=12x3x2+12=12x 3x2−12x+12=03x2−12x+12=0

Divide the equation by 3: x2−4x+4=0x2−4x+4=0

Factorize: (x−2)2=0(x−2)2=0

So, x=2x=2.

Now, substitute x=2x=2 into equation (2) to find yy: 2y=62y=6 y=3y=3

So, x=2x=2 and y=3y=3.

Step 2: Find the value of 9x2+4y29x2+4y2

Substitute the values of xx and yy into the expression 9x2+4y29x2+4y2: 9(2)2+4(3)29(2)2+4(3)2 9(4)+4(9)9(4)+4(9) 36+3636+36 7272

Conclusion: The value of 9x2+4y29x2+4y2 is 7272.

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Answered on 18 Apr Learn Polynomials

Nazia Khanum

Factorization of Polynomials Using Factor Theorem Introduction Factorization of polynomials is a fundamental concept in algebra that helps in simplifying expressions and solving equations. The Factor Theorem is a powerful tool that aids in factorizing polynomials. Factor Theorem The Factor Theorem... read more

Factorization of Polynomials Using Factor Theorem


Introduction

Factorization of polynomials is a fundamental concept in algebra that helps in simplifying expressions and solving equations. The Factor Theorem is a powerful tool that aids in factorizing polynomials.


Factor Theorem

The Factor Theorem states that if f(c)=0f(c)=0, then (x−c)(x−c) is a factor of the polynomial f(x)f(x).


Factorization of Polynomial x3−6x2+3x+10x3−6x2+3x+10

  1. Step 1: Find Potential Roots

    • Potential roots can be found by setting f(x)=0f(x)=0 and solving for xx.
    • Possible rational roots are determined using the Rational Root Theorem.
  2. Step 2: Test Roots Using Factor Theorem

    • Test the potential roots by substituting them into the polynomial.
    • If f(c)=0f(c)=0, then (x−c)(x−c) is a factor.
  3. Step 3: Synthetic Division

    • Perform synthetic division to divide the polynomial by the found factor.
    • Repeat the process until a quadratic polynomial is obtained.
  4. Step 4: Factorization

    • Factor the quadratic polynomial using methods like quadratic formula or decomposition.

Factorization of x3−6x2+3x+10x3−6x2+3x+10

  1. Potential Roots:

    • Potential rational roots are ±1,±2,±5,±10±1,±2,±5,±10.
  2. Testing Roots:

    • By testing, it's found that x=−2x=−2 is a root.
  3. Synthetic Division:

    • Perform synthetic division:
      (x3−6x2+3x+10)÷(x+2)(x3−6x2+3x+10)÷(x+2)

    • This yields the quotient x2−8x+5x2−8x+5.

  4. Factorization of Quotient:

    • The quadratic polynomial x2−8x+5x2−8x+5 can be factored as (x−5)(x−1)(x−5)(x−1).
  5. Final Factorization:

    • x3−6x2+3x+10=(x+2)(x−5)(x−1)x3−6x2+3x+10=(x+2)(x−5)(x−1).

Factorization of Polynomial 2y3−5y2−19y2y3−5y2−19y

  1. Potential Roots:

    • For a polynomial of the form 2y3−5y2−19y2y3−5y2−19y, potential rational roots are ±1,±12,±19,±192±1,±21,±19,±219.
  2. Testing Roots:

    • By testing, it's found that y=0y=0 is a root.
  3. Synthetic Division:

    • Perform synthetic division:
      (2y3−5y2−19y)÷y(2y3−5y2−19yy

    • This yields the quotient 2y2−5y−192y2−5y−19.

  4. Factorization of Quotient:

    • The quadratic polynomial 2y2−5y−192y2−5y−19 cannot be factored further using integer coefficients.
  5. Final Factorization:

    • 2y3−5y2−19y=y(2y2−5y−19)2y3−5y2−19y=y(2y2−5y−19).

Conclusion

Factorizing polynomials using the Factor Theorem involves identifying potential roots, testing them, performing synthetic division, and factoring the resulting quotient. This method simplifies complex expressions and aids in solving polynomial equations effectively.

 
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Answered on 18 Apr Learn Polynomials

Nazia Khanum

What is the number of zeros of the quadratic equation x2+4x+2x2+4x+2? Answer: Quadratic Equation: x2+4x+2x2+4x+2 To determine the number of zeros of the quadratic equation, we can use the discriminant method: Discriminant Formula: The discriminant, denoted by Δ, is calculated using the formula:... read more

What is the number of zeros of the quadratic equation x2+4x+2x2+4x+2?

Answer:

Quadratic Equation: x2+4x+2x2+4x+2

To determine the number of zeros of the quadratic equation, we can use the discriminant method:

  1. Discriminant Formula:

    • The discriminant, denoted by Δ, is calculated using the formula: Δ=b2−4acΔ=b2−4ac, where aa, bb, and cc are the coefficients of the quadratic equation ax2+bx+cax2+bx+c.
    • In our equation, a=1a=1, b=4b=4, and c=2c=2.
  2. Calculating Discriminant:

    • Δ=(4)2−4(1)(2)Δ=(4)2−4(1)(2)
    • Δ=16−8Δ=16−8
    • Δ=8Δ=8
  3. Interpreting the Discriminant:

    • If Δ>0Δ>0, the quadratic equation has two distinct real roots.
    • If Δ=0Δ=0, the quadratic equation has one real root (a repeated root).
    • If Δ<0Δ<0, the quadratic equation has no real roots (complex roots).
  4. Result:

    • Since Δ=8>0Δ=8>0, the quadratic equation x2+4x+2x2+4x+2 has two distinct real roots.

Conclusion: The number of zeros of the quadratic equation x2+4x+2x2+4x+2 is two.

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