1.3 - Cardinality of sets 1. Let A,B, C are the three sets, then n(A)=17, n(B)=17, n(C)=17, n(BnC)=6, n(AnC)=5, and n(AnBnC)=2 then find n(AUBUC). Solution: n(AUBUC). = n(A) + n(B) + n(C) - n(AnB)-....
Before starting the discussion I would like to mention this problem The conventional way to solve this problem is to deal with trigonometric identities...
Q: The numerator of a fraction is 3 less than the denominator. If 2 is added to both the numerator and the denominator, then the sum of the new and the original fraction is 29/20. Find the...